@bahrom7893

Question

@bahrom7893

ineedhelp10 · Answer

What is the least value of x that satisfies the equation: x^2-7x+6=6
a)-7
b)-6
c)-4
d)0
e)1

bahrom7893 · Answer

what is?
(-7)^2-7*(-7)+6?

uri · Answer

Plug in each answer option in the equation and check.

bahrom7893 · Answer

Just plug each in and see which one satisfies it.

ineedhelp10 · Answer

i got 104 for -7

bahrom7893 · Answer

and then pick the smallest one

ineedhelp10 · Answer

oh ok so im supposed to get 6 as the answer?

ineedhelp10 · Answer

but i dont get how im supposed to pick the "least value" like what does that mean?

bahrom7893 · Answer

yea, and then pick the smallest value, let's say 1 and 2 satisfy it. 1 is smaller than 2 so 1 is your answer.

uri · Answer

yeah the answer should come 6,so see which answer option is satisfying it.

ineedhelp10 · Answer

for -6 i got 84
-4=50
0=6
1=0

ineedhelp10 · Answer

does that mean that the least value will be e.1 because i got 0

mathstudent55 · Answer

Since this is a simple quadratic, it may take less time to solve it that to plug in all the choices.

$x^2-7x+6=6$

$x^2-7x=0$

$x(x - 7) = 0$

x = 0 or x - 7 = 0

x = 0 or x = 7

Now pick the smaller value that is a choice.

ineedhelp10 · Answer

x=0

mathstudent55 · Answer

Correct.

ineedhelp10 · Answer

so then the correct answer choice is E, correct?

mathstudent55 · Answer

Isn't d) 0?

mathstudent55 · Answer

e) is 1
You need 0 not 1, so the answer is d).

ineedhelp10 · Answer

oh i got confused because when i plug in 1 into the equation i got 0, thats why i tought it was e

mathstudent55 · Answer

When you plugged in 1, the left side of the equation turned out to be 0. You are correct. The problem is that for 1 to satisfy the equation, it would have to cause the left side to evaluate to a value of 6 since the right side is 6.

ineedhelp10 · Answer

oh ok i get what you're saying, so then the answer is D

mathstudent55 · Answer

In a case like this, it is better to move everything to the left side first, and then evaluate each choice.
In this case, it would be:

$x^2-7x+6=6$   Subtract 6 from both sides

$x^2 - 7x = 0$

Now evaluate the left side for all the given choices and see which one comes out to be zero.

a) $(-7)^2 - 7(-7) = 98$

b) $(-6)^2 - 7(-6) = 78$

c) $(-4)^2 - 7(-4) = 44$

d) $(0)^2 - 7(0) = 0$

e) $(1)^2 - 7(1) = -6$

d) is the only choice that evaluates to 0, so the answer is d) x = 0

mathstudent55 · Answer

Yes, that's it.

ineedhelp10 · Answer

thank you so much for your help! i appreciate it!

mathstudent55 · Answer

You're welcome.