A body is thrown with velocity 100m/s, it travels 5m in last second of its upward journey. if the same body is thrown with velocity 200m/s, what distance will it travel in last second of its upward journey?

Question

cp9454 · Answer

@LarsEighner

anonymous · Answer

The velocity is doubled here from 100 to 200 meters per second what do you think will happen to the distance based on the formula for velocity.

Velocity:$$ velocity = \frac{ \Delta x }{ \Delta t }$$

Where x is the displacement and t is the time.

anonymous · Answer

this problem is of Freely Falling bodies... the given velocities are simply initial... and gravitational pull of the Earth has an effect to its upward journey...

anonymous · Answer

... the appropriate formula... $$h=v_ot-\frac{1}{2}gt^2$$ where $$h~is~the~height~or~distance~travelled~by~the~thrown~body$$$$v_o,~the~given~initial~velocity$$$$t~is~the~time~travelled$$$$g=9.8~m/sec^2,~gravitational~accelereration~due~to~Earth's~gravity$$