the expression ax^3-8x^2+bx+6 is divisible by x^2-2x-3.Find the values of a and b. @eric_d
say `g(x) = x^2-2x-3` we're given `g(x)` divides the given expression, so can we say that the individual factors of `g(x)` also divide the given expression ?
*
ok..
can you factor `g(x)` ?
(x-3)(x+1)
Excellent ! that means `x-3` and `x+1` are factors of given expression, right ?
ys
i dnt know how u manage that much of question :-\
i dnt know how u manage that much of question
You mean Ganesh ? @ikram002p
hehe , yeah :P
:P
good :) so we appeal to factor/remainder theorem : if `x-a` is a factor of f(x), then `f(a) = 0`
ok..
Well isn't this like saying if we have the number 72 and I tell you it is divisible by 6 does this mean that 72 is also divisible by 3 and 2?
yep the same kai
exactly ^^ @eric_d thats a very good analogy to see why the factors of `f(x)` must also divide the given expression
since `x-3` and `x+1` are factors of given expression also, can we use factor/remainder theorem and get two equations in a and b ? can you try ?
sure
27a+3b-66 .....1 -a-b+2 ......2 like this
Perfect !
two equations and two unknowns, not very exciting, anybody can solve them :)
When solving simultaneously, I'm getting a=2.5 ??
isolved the question in defferent way , but i got 3 mmm which make no sense cuz this way is correct as well
You can show ur working here
is b = 13 ?
the given answer is b=-5
ok this is what i did |dw:1406449362560:dw|
|dw:1406449576959:dw|
@eric_d there is a small typo in ur equations which ive overlooked earlier : 27a+3b-66 =0.....1 -a-b\(\color{Red}{-}\)2 =0 ......2 solving gives you http://www.wolframalpha.com/input/?i=solve+27a%2B3b-66%3D0%2C-a-b-2%3D0
hehe perfect xD
So, I can't solve the eqn simultaneously
@ikram002p
-a-b=2 27 a +3b =66 mmm xD -3a-3b =6 + 27 a+3b =66 ـــــــــــــــــــــــــــــــــــــــــ 24a=66+6=27 mmm u know find a
Okay
Understood.. Thank you @ganeshie8 @ikram002p @Kainui
sorry i made to many typo xD 66+6= 72
It's alrite
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