The electric field, at a distance of 20 cm from the center of a dielectric sphere of radius 10 cm is 100 N/C. Then Electric field intensity at 3 cm distance from the center of sphere is ?
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OpenStudy (abhisar):
@vishweshshrimali5 @Vincent-Lyon.Fr
OpenStudy (abhisar):
@Abmon98
OpenStudy (vishweshshrimali5):
Okay lets see how much I remember ;)
OpenStudy (abhisar):
;)
OpenStudy (vishweshshrimali5):
You would be knowing the formula for electric field due to a charged sphere ?
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OpenStudy (abhisar):
yes
OpenStudy (abhisar):
I am using gauss law
OpenStudy (vishweshshrimali5):
Great. You can use Gauss' law to find out the formula for electric field
OpenStudy (vishweshshrimali5):
\[\large{E = k\cfrac{Q}{r^2}}\]
OpenStudy (vishweshshrimali5):
I am not using the vectorial form
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OpenStudy (abhisar):
that's ok
OpenStudy (abmon98):
i am sorry i have no idea @Abhisar
OpenStudy (abhisar):
It's ok @Abmon98 !
Thanx for responding :)
OpenStudy (vishweshshrimali5):
I used that formula because distance of separation > radius of sphere
OpenStudy (vishweshshrimali5):
Here:
r = 20 cm = 0.2 m
E = 100 N/C
Using this we can find out the value k
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OpenStudy (vishweshshrimali5):
* the value of kQ
OpenStudy (abhisar):
I got it :D
OpenStudy (vishweshshrimali5):
Now for the next part since distance of separation < radius of sphere
Thus the formula would be:
\[\large{E = \cfrac{kQr}{R^3}}\]
OpenStudy (abhisar):
what is the answer you getting btw ?
OpenStudy (vishweshshrimali5):
Will have to calculate it ... Just a minute :)
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OpenStudy (abhisar):
yeah sure !
OpenStudy (vishweshshrimali5):
120 N/C ?
OpenStudy (abhisar):
lol..i am getting 1200 N/c....must be a mistake in conversion