Question

Please Help!!

Find an equation in standard form for the ellipse with the vertical major axis of length 6, and minor axis of length 4.

Answer 1

\[\frac{ x ^{2} }{ 2 }+\frac{ y^{2} }{ 3 }=1 \]
\[\frac{ x ^{2} }{ 9 } +\frac{ y ^{2} }{ 4 }=1\]
\[\frac{ x ^{2} }{ 3 }+\frac{ y ^{2} }{ 2 }=1\]
\[\frac{ x ^{4} }{4 }+\frac{ y ^{2} }{ 9 }=1\]

Answer 2

for the last one it should be x^2

Answer 3

@SolomonZelman @precal

Answer 4

@mathstudent55

Answer 5

I haven't done ellipses for a while... I'll read my book to rvw this for a little and if no one helps....

Answer 6

ok, thank you :)

Answer 7

standard form of the ellipse is assuming that the center is the origin ?

Answer 8

Assuming that (0,0) (the origin) is the center


\(\LARGE\color{blue}{ \frac{x^2}{2^2} +\frac{y^2}{3^2}\rm =1 }\)


\(\LARGE\color{black}{ \frac{x^2}{4} +\frac{y^2}{9}=1~~~~~~~\frak {✓} }\)

Answer 9

saying that vertical axis is 6 so 3 from the (0,0) up, and 3 down.

An so we go 2 and 2 horizontally

Answer 10

oh my gosh i get it!

Answer 11

thank you!!

Answer 12

Anytime !

Answer 13

can you check if i got this one right?

Answer 14

Find the center, vertices, and foci of the ellipse with equation
\[\frac{ x ^{2} }{ 100}+\frac{ y ^{2} }{ 64}=100\]

Answer 15

i said:
Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-6, 0), (6, 0)

Answer 16

@SolomonZelman

Answer 17

Looks like you are correct.

Answer 18

oh geez, that second 100 should be a 1

Answer 19

ok, thank you :)

Answer 20

did you just now say that the question is wrong ?

Answer 21

no the question is right, i wrote it wrong, it should be
\[\frac{ x ^{2} }{ 100}+\frac{ y^{2} }{ 64}=1\]

Answer 22

Oh.. that! I realized that :) Or otherwise I would have told you to divide everything by 100 .

Answer 23

ohh haha ok :)