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Calculus1 18 Online
OpenStudy (anonymous):

Find all relative extrema of the function. (If an answer does not exist, enter DNE.) f(x) = x^2 + 2x + 14

OpenStudy (aaronq):

"extrema" as in minima and maxima?

OpenStudy (aaronq):

If so, take the first derivative and set it equal to zero. Find all the solutions (values of x where this is true). With the original function, determine whether these points are minima or maxima by taking points just before and just after.

OpenStudy (anonymous):

so if I take the first derivative it would be f'=2x+2 and then setting it to zero would look like f'=2x+2=0, then if x=-1 it would then equal 0. So would I then take the limit as it approaches x at -1 for f(-1)=x(-1)^2+2(-1)+14?

OpenStudy (aaronq):

im not sure if this is what the question is askin for, is it this? |dw:1406496364992:dw|

OpenStudy (anonymous):

I'm not sure what extrema is.. let me see what else i can find out...

OpenStudy (anonymous):

This is what it looks like

OpenStudy (aaronq):

oh okay, yeah thats what it is http://en.wikipedia.org/wiki/Maxima_and_minima

OpenStudy (anonymous):

it looks like it is asking for 4 points

OpenStudy (anonymous):

would I then put -1, 0 and then 0, -1?

OpenStudy (aaronq):

no, thats not right. I'm not sure, look at the graph http://www.wolframalpha.com/input/?i=x%5E2%2B2x%2B14

OpenStudy (aaronq):

theres only 1 minimum, the maxima at both ends is infinity

OpenStudy (anonymous):

soo looking at the link it says global minimum is -1? I'm not sure how to input it for (x,y). That means x=-1 and y=0 right? and then the maxima would be 0,inf?

OpenStudy (aaronq):

it would be ( -1, f(-1) ) f(-1) is what you found above

OpenStudy (aaronq):

then maxima \(\pm \infty\), not sure how you're supposed to format it

OpenStudy (aaronq):

no, i dont open word files from the internet.

OpenStudy (aaronq):

sure, or you can post it as a pdf, which would be quicker

OpenStudy (anonymous):

OpenStudy (aaronq):

relative maximum DNE relative min: (-1, 13)

OpenStudy (anonymous):

so there is no maximum? and for the bottom two i just had to solve for it? that isn't so bad. :)

OpenStudy (aaronq):

it's not eh! :) the main point of this is to take the derivative and find where f'(x)=0, those are the "turning points" of the graph, where the slope is horizontal. Then determine whether those points are maxima or minima.

OpenStudy (anonymous):

oh ok! Thank you for explaining it to me. I hope it sticks long enough to take my next test! :)

OpenStudy (aaronq):

haha write it down! :P but no problem!

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