Question

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle.

2 to the 3 over 5 power inches squared

2 to the 4 over 5 power inches squared

2 inches squared

2 to the 2 over 5 power inches squared



to me this looks like a foreign language!!!!! HELP?!

Answer 1

\[\sqrt[5]{16}\times 2^{\frac{1}{5}}\] i guess is what they are asking for
weird to mix up the radical and exponential notation

Answer 2

I still don't get it

Answer 3

:(

Answer 4

\[16^{\frac{1}{5}}\times 2^{\frac{1}{5}}\]

Answer 5

since \(16=2^4\) this is
\[\large 2^{\frac{4}{5}}\times 2^{\frac{1}{5}}\]

Answer 6

????????????
im really sorry but math aint my strongest subject

Answer 7

add up the exponents, get
\[\huge 2^{\frac{4}{5}+\frac{1}{5}}=2^{\frac{5}{5}}=2^1=2\]

Answer 8

so is it the second answer choice??

Answer 9

or C

Answer 10

it is C!!! 2 inches squared

Answer 11

can you help me with a couple other ones??

Rewrite the radical as a rational exponent.

the cube root of 2 to the seventh power

Answer 12

\[\huge \sqrt[3]{2^7}=2^{\frac{7}{3}}\]

Answer 13

ok thank you so much

Answer 14

can you help with 3 more?? I don't want to bother but I only got an hour left to finish 2 tests

Answer 15

\[\huge \sqrt[\color{red}n]{x^\color{blue}m}=x^{\frac{\color{blue}m}{\color{red}n}}\]

Answer 16

k shoot

Answer 17

Explain how the Quotient of Powers was used to simplify this expression.

5 to the fourth power, over 25 = 52

By simplifying 25 to 52 to make both powers base five, and subtracting the exponents

By simplifying 25 to 52 to make both powers base five, and adding the exponents

By finding the quotient of the bases to be, one fifth and cancelling common factors

By finding the quotient of the bases to be, one fifthand simplifying the expression

Answer 18

\[\frac{5^4}{25}=\frac{5^4}{5^2}=5^{4-2}=5^2=25\]

Answer 19

i would go with
By simplifying 25 to \(5^2\) to make both powers base five, and subtracting the exponents

Answer 20

Rewrite the rational exponent as a radical expression.

3 to the 2 over 3 power, to the 1 over 6 power

the sixth root of 3

the ninth root of 3

the eighteenth root of 3

the sixth root of 3 to the third power

Answer 21

\[\huge (3^{\frac{2}{3}})^{\frac{1}{6}}\] like that ?

Answer 22

i suppose it is
then you get
\[\large 3^{\frac{1}{9}}=\sqrt[9]{3}\]

Answer 23

the sixth root of 3

the ninth root of 3

the eighteenth root of 3

the sixth root of 3 to the third power

these are the answer choices

Answer 24

go with the ninth root of three

Answer 25

ok thnx

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 3 over 4 power, all over 2 to the 1 over 2 power

the eighth root of 2 to the third power

the square root of 2 to the 3 over 4 power

the fourth root of 2

the square root of 2




that's the last one

Answer 26

\[\huge \frac{2^{\frac{3}{4}}}{2^{\frac{1}{2}}}=2^{\frac{3}{4}-\frac{1}{2}}=2^{\frac{1}{4}}\]

Answer 27

or
\[\huge \sqrt[4]{2}\]

Answer 28

omg!!!! thank you so much!!! I really owe you somehow!!!!!!!!

Answer 29

lol good luck with the rest of your tests

Answer 30

thanks
and its 10/10 right

Answer 31

yay!

Answer 32

I gave you a whole bunch of medals

Answer 33

thanks
now if i could only redeem them for valuable prizes....

Answer 34

yeah that would be great. you'd be rich then