Why would you subtract the heat of a calorimeter when calculating heat of the reaction? hint: the heat of the calorimeter is the amount of heat that the calorimeter absorbs from the solution-each calorimeter will absorb a certain amount of heat, which means that the temperature change that you measure is actually less that the ideal temperature change.
you mean subtract product from reactant or subtract what ??
Oh sorry I made a typo. Why would you subtract the heat capacity of the calorimeter when calculating the heat of reaction
Dela T = T final - T initial. T final is bigger then it gain energy(take heat),so you have to put -ve sign to get - value which means taking. T final is smaller then it lose energy (deliver heat), so you have to put - sign to get + value which means producing. The negative sign indicates that the calorimeter is gaining energy and the water in the calorimeter is losing energy. http://www.physicsclassroom.com/class/thermalP/Lesson-2/Calorimeters-and-Calorimetry
Ok i got it thanks a lot!
you are welcome. that minus sign don't call it subtract ( i imagined that you will subtract it from the product).
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