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Mathematics 18 Online
OpenStudy (anonymous):

Help with trig finding the exact value. Screenshot is attached

OpenStudy (anonymous):

OpenStudy (amilapsn):

|dw:1406493311282:dw|

OpenStudy (amilapsn):

ok?

OpenStudy (anonymous):

Okay

OpenStudy (kva1992):

5 12 13 is a triangle you remember quite a bit so sin would equal 5/13

OpenStudy (amilapsn):

What's the expansion of \[\sin (\alpha+\beta)\]?

OpenStudy (kva1992):

well once you get sin a and sin b you would use your identity

OpenStudy (kva1992):

which is sinA cosB +cosA sin B

OpenStudy (amilapsn):

hey kva let him try!

OpenStudy (kva1992):

oh snaps lol i thought you were him my bad lol

OpenStudy (amilapsn):

lol

OpenStudy (amilapsn):

@oroutdoors hey where are you?

OpenStudy (kva1992):

lol

OpenStudy (anonymous):

Sorry I stepped away for a minute! its sina cosb - cosa sinb??

OpenStudy (kva1992):

correct

OpenStudy (kva1992):

do you know how to get your sin a and sin b? or remember?

OpenStudy (anonymous):

No thats where I keep messing up

OpenStudy (kva1992):

alright well lets start with the easier one

OpenStudy (kva1992):

so cos b is 5/6 correct?

OpenStudy (anonymous):

correct

OpenStudy (kva1992):

alright draw a triangle so you can find sin b

OpenStudy (amilapsn):

sin(a+b) is not equal to sinacosb - cosasinb!!

OpenStudy (kva1992):

yeah it is

OpenStudy (anonymous):

;-/ haha

OpenStudy (kva1992):

its the identity

OpenStudy (kva1992):

go double check that if you dont believe me

OpenStudy (amilapsn):

look back your books!!

OpenStudy (kva1992):

look at the formula

OpenStudy (kva1992):

sin(a+b) = sinacosb+cosasinb sin(a-b) = sinacosb-cosasinb

OpenStudy (kva1992):

back to what i was saying

OpenStudy (amilapsn):

ok

OpenStudy (kva1992):

|dw:1406494404902:dw|

OpenStudy (kva1992):

so this will give you your sin a

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

Okay thats where I keep screwing up

OpenStudy (amilapsn):

\[\sin (\alpha+\beta)=\frac{ 25-12\sqrt{11} }{ 78}\]

OpenStudy (anonymous):

Ya

OpenStudy (anonymous):

So far haha

OpenStudy (anonymous):

sin 5/13 cos 12/13?

OpenStudy (anonymous):

I'm not getting it

OpenStudy (anonymous):

I think i'm with you for the most part haha. Should I go ahead and plug those in?

OpenStudy (anonymous):

Did you delete what you had?

OpenStudy (kva1992):

figured you didnt need it lol

OpenStudy (kva1992):

if you do i can retype it lol not gonna take too long to do so

OpenStudy (anonymous):

No it's okay I just scrolled back down and wasn't sure

OpenStudy (kva1992):

btw do you have the answer key?

OpenStudy (anonymous):

No I don't

OpenStudy (anonymous):

This is my last chance so I'm nervous to put in an answer ;-/

OpenStudy (kva1992):

ahh got ya well lemme double check before you put it in

OpenStudy (kva1992):

it would have to be that method for the first one second one it would be a different identity but same value and tan would be the same

OpenStudy (kva1992):

but double check its the right formula

OpenStudy (anonymous):

Ok hold on

OpenStudy (kva1992):

its on the right side sum difference formula

OpenStudy (anonymous):

The method they want me to use in the example I get the answer 25/78-2root11/13

OpenStudy (kva1992):

well go with what the example they use maybe i miscalculated not a computer after all lol

OpenStudy (kva1992):

but i know i used the right formula for a fact

OpenStudy (kva1992):

oh snaps lol i wrote the cosb wrong lol i used the reciprocal

OpenStudy (kva1992):

gimme 1 sec and ill give you the proper values

OpenStudy (anonymous):

Thanks for your help! @amilapsn had the right answer the program didn't like how I entered it of well lol

OpenStudy (kva1992):

the values were (5/13)(5/6)+(12/13)(square root 11/6)

OpenStudy (kva1992):

so it would have resulted in the same answer

OpenStudy (anonymous):

Yes

OpenStudy (kva1992):

accidentally flipped the 5/6 to 6/5

OpenStudy (kva1992):

sorry for wasting your time i guess lol

OpenStudy (anonymous):

No I appreciate your help! don't be sorry!

OpenStudy (anonymous):

for part b -10/13-5root11/78?

OpenStudy (anonymous):

is that what you get @amilapsn

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