Question

integral of [e^arcsin(x)] dx /[sqrt(1-x^2)]

Answer 1

Easier than it looks ;)

Answer 2

haha I can see the sqrt(1-x^2) in denominator will lead to arcsin x

Answer 3

Tell me, what's \(\Large \frac{d}{dx} ~sin^{-1}x\)

Answer 4

\[1\div(\sqrt{1-x ^{2}}\]

Answer 5

Use a u-sub and get this little thing :)
\[\Large \int e^u~du\]

\(\Large u=arcsinx \) so that means \(\Large du=\frac{1}{\sqrt{1-x^2}} dx\)

Answer 6

you can also do this question by substituting x=sinz

Answer 7

Excellent!
Thank you!

Answer 8

wow.. that really was easier haha

Answer 9

You're welcome~