What is the rate of change for f(x) = −2 cos(4x − 3) on the interval from x = pi / 4 to x = pi / 2? A. -pi / 16 B. -16 / pi C. 2 / pi D. pi / 2
@mathstudent55
@desuoverlord
@precal
just sub and use the slope formula
I have no idea on how to sub
really this is an advance math problem......precal or calculus level
strange, maybe you are in the wrong course
im taking an algebra 2 honors class
still you have sub before example f(x)=2x+3 find f(4)
11
see you know how to sub
sub pi/4 into f(x)
4.57079...
no leave in radian
(pi / 2) + 3
so D!
did you do the second substitution?
pi over 4?
what? I got pi / 2
no remember you need to use the slope formula with both of them
so I still need to find 'y'.
[f(π/2)−f(π/4)]/[(π/2)−(π/4) ]
remember difference of y over difference of x, slope formula
1
is that right??
no, I don't think so, is it cos(4x-3) or cos(4x)-3 ?
-2cos(4x - 3)
need to check with my graphing calculator
none are working out, are you sure you wrote the problem correctly?
@bahrom7893 can you double check me?
yes...
What is the rate of change for f(x) = −2 cos (4x − 3) on the interval from x = pi over 4 to x = pi over 2?
(f(x2) - f(x1))/(x2 - x1) should give you the answer
that makes no sense, are you solving for x?
This is also a strangely worded question, do you mean AVERAGE rate of change? The rate of change over that interval is defined using the derivative and is used to show how the function is changing at a specific point. The average rate of change is 4cos(3)~-4, which is what these guys already said.
when I did the pi/2 sub I got -2cos(4(pi/2)-3) -2 cos(2pi-3) can I simplify it anymore?
but she said she is in Algebra II honors, that doesn't make any sense
Algebra II doesn't do derivatives
yeah, I didn't use it, just confirming what the question was, usually you would say average rate of change for this type of question.
this is the final chapter in the class which is all about trig
^^so how would you figure out to answer
are you sure your problem is not -2cos(4x)-3 because it makes a big difference
the orig. problem has no parenthesis
http://i.imgur.com/k5T5d62.png I have done it via calculator, there is no way it is one of those answers.
I believe it is what I wrote -2cos(4x)-3 -2cos(4(pi/2))-3 -2 cos2pi -3 -2(0)-3 0-3 -3
could it be B, since there is a neagative , 16 on top, and pi on the bottom?
-2cos(4x)-3 -2cos(4(pi/4))-3 -2 cos(pi )-3 -2(-1)-3 2-3 -1 we don't guess in math
-3--1=-3+1=-2 on top
(pi/2)-(pi/4) 2pi/4 - pi/4 pi/4
-2 over pi/4 -2 times 4/pi -8/pi
strange none look like that
x2 = B
@sylbot I got what you got earlier with my graphing calculator, see any mistakes on my part
There must be an error in precal's work, I'm getting B as the answer, adjusting for the parenthesis (the -3 is outside) let me work it out tho. http://i.imgur.com/Tjrb6bK.png Ignore the bottom.
yes pi over 2 is -5
-4 over pi/4 -4 times 4/pi -16/pi
thanks so much! do youhave time for one more question
yes it is B btw the -3 is outside of the ( ) and that does matter
I found the error, precal cos(pi)=1 not zero.
correct its -1 and I found the mistake as well close this problem and start a new thread
oo0ooooops cos(2pi)=1
believe it is what I wrote -2cos(4x)-3 -2cos(4(pi/2))-3 -2 cos2pi -3 -2(0)-3 0-3 -3 here it was haha could happen to anyone, glad you got the help you need in the end.
@sylbot cos (2 pi) is 1 -2(1)-3 -2-3 -5 and this is where I made the mistake but you were right thanks for catching it
Join our real-time social learning platform and learn together with your friends!