Question

Simplify

Answer 1

\[\left( -5a^2b^4 \right)a^-7b^2/b^8\]

Answer 2

\[\large \frac{-5a^2b^4a^{-7}b^2}{b^8}\]?

Answer 3

yes

Answer 4

add up the exponents
\[\frac{-5a^{-5}b^6}{b^8}\]

Answer 5

then maybe
\[\frac{-5}{a^5b^2}\] if you wand only positive exponents

Answer 6

you subtracted b^6 from b^8?

Answer 7

i subtracted 6 from 8

Answer 8

sorry the question is \[\frac{ (-5a^2b^4)^3 a^-7b^4 }{ b^8 }\]

Answer 9

well then you get a totally different answer
first multiply each exponent in the parentheses by 3

Answer 10

then proceed as before by adding the exponents with the like bases

Answer 11

-5a^6b^12a_7b^4/b^8

Answer 12

no should be \(-125\) cause you have to cube that one too

Answer 13

\[\frac{ -5a^-1b^6 }{ b^8 }\]

Answer 14

\[\frac{-125a^6b^{12}a^{-7}b^4}{b^8}\]

Answer 15

then
\[\frac{-125a^{-1}b^{16}}{b^8}\]

Answer 16

finally
\[\frac{-125b^8}{a}\]

Answer 17

I see, you multipled everything in the bracket by 3

Answer 18

why did you use a as denominator this time

Answer 19

multiplied each exponent by 3
the \(-5\) got cubed

Answer 20

because \(a^{-1}=\frac{1}{a}\) since it was in the top i brought it down

Answer 21

Okay

Answer 22

Thank you @satellite73