anyone want to explain why the graphing calculator doesn't give a complete graph of
y = ln(x)

Question

anyone want to explain why the graphing calculator doesn't give a complete graph of 
y = ln(x)

anonymous · Answer

what does a graphing calculator ever give a "complete" graph of?

vishweshshrimali5 · Answer

y = ln (x)

is NOT defined for $x \le 0$

vishweshshrimali5 · Answer

Probably this is the reason ^^^

precal · Answer

but it doesn't have a start point or endpoint like the square root function

solomonzelman · Answer

You can graph it by hand it would be uncomfortable to do it though.

vishweshshrimali5 · Answer

It does not have a minimum value or a maximum value.

vishweshshrimali5 · Answer

ln(x) approaches -infty as x approaches zero

And ln(x) approaces infty as x approaches inty

vishweshshrimali5 · Answer

No maximum or minimum value

vishweshshrimali5 · Answer

No start point because as x > 0, y is defined

anonymous · Answer

$$y=2x+1$$ doesn't either
never heard you complaining about that one a calculator
picky picky

vishweshshrimali5 · Answer

:D Lol

vishweshshrimali5 · Answer

No end point because y does not END anywhere

vishweshshrimali5 · Answer

It just goes on and on and on and on and more on..... :P ;)

precal · Answer

ok that was my next question about the limits of ln(x)
@vishweshshrimali5 thanks for clearly that

vishweshshrimali5 · Answer

:D Your welcome :)