Question

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

Factor completely 2x3 + 10x2 + 4x + 20.

Answer 1

@ganeshie8 @satellite73 @shadow.655 @SolomonZelman @jim_thompson5910

Answer 2

\(\normalsize\color{blue}{ 2x^3 + 10x^2 + 4x + 20 }\) lets look at this,

\(\normalsize\color{blue}{ \underline{ 2x^3 + 10x^2} + \underline{ 4x + 20} }\)

\(\normalsize\color{blue}{ \underline{ \color{red}{(2x^2)}x + \color{red}{(2x^2)}5} + \underline{ \color{red}{(4)}x + \color{red}{(4)}5} }\)

Answer 3

\[2x^3 + 10x^2 + 4x + 2\] i would start with
\[2(x^3+5x^2+2x+1)\] and then since i suck at factoring i would cheat

Answer 4

Try it.

Answer 5

I have no idea what to do

Answer 6

oh it is a 20 much easier
i would still cheat

Answer 7

satelite please help with my problem next

Answer 8

what do you mean @satellite73 ?

Answer 9

you can try to finish what I started. See what I was doing ?

Answer 10

not really. this is new information that i don't really get yet.

Answer 11

\(\normalsize\color{black}{\underline{ 2x^3+10x^2\color{red}{ } }+ \underline{4x+20} }\) see what I did juts now ?

Answer 12

no

Answer 13

\(\normalsize\color{black}{ 2x^3+10x^2\color{red}{ } + 4x+20 }\)

\(\normalsize\color{black}{\underline{ 2x^3+10x^2\color{red}{ } }+ \underline{4x+20} }\) I underlined 2 parts of it right ?

Answer 14

yeah

Answer 15

\(\normalsize\color{black}{\underline{ x\color{red}{(2x^2) }+5\color{red}{(2x^2) } }+ \underline{4x+20} }\)

then I am re-writing `2x³` as `x × (2x²)` and `10x²` as `5 × 2x²`

right ?

Answer 16

yeah

Answer 17

I can factor the first underlined part, correct?
\(\normalsize\color{black}{\underline{ x\color{red}{(2x^2) }+5\color{red}{(2x^2) } }+ \underline{4x+20} }\)

Answer 18

I can factor the first part out of `2x²` right ?

Answer 19

right

Answer 20

\(\normalsize\color{black}{\underline{ \color{red}{2x^2 }(x+5)\color{red}{ } }+ \underline{4x+20} }\) like this, right ?

Answer 21

right

Answer 22

\(\normalsize\color{black}{\underline{ \color{red}{2x^2 }(x+5) }+ \underline{\color{red}{(4)}x+\color{red}{(4)}5} }\) what did I do now ?

Answer 23

See ?

Answer 24

I think i get it

Answer 25

Okay, can you factor the second underlined part ?

Answer 26

factor the second underlined part out of 4.

Answer 27

um, would it be 2?

Answer 28

you are taking 4 out of each thing, so if I had
\(\normalsize\color{black}{ \underline{\color{red}{(b)a+\color{red}{(b)}c}} }\) I would then get ` b(a+c)`

Answer 29

oh..it would be 4(x + 5) right ?

Answer 30

Yes !

Answer 31

So we are going to get

\(\normalsize\color{black}{\underline{ \color{red}{2x^2 }(x+5) }+ \underline{\color{red}{4}(x+5)} }\)

Answer 32

can you finish factoring ?

Answer 33

Just another, last step....

Answer 34

d(c+v)+h(c+v) → (d+h)(c+v)

Answer 35

So in your case, you get ?

Answer 36

Do you get 2(x+5) (x^2+2)?

Answer 37

Yes

Answer 38

Good job:D

Answer 39

thanks 4 ur help! :) <3

Answer 40

Anytime !