Question

WILL GIVE MEDAL! PLEASE help???.. Attached in the comments section is the problem.. It's a picture of a graph and I need to know if it's greater than or less than 0

Answer 1

Not sure how to do this one

Answer 2

It's a greater than or less than 0 question

Answer 3

PLEASE???? Somebody please help????

Answer 4

the function is increasing so the derivative is ?
your choice is "positive" or "negative"

Answer 5

How do I find the derivative from this?

Answer 6

My guess is the derivative is positive too? but what about f" ?? is that positive too?

Answer 7

not "positive too" just "positive"

Answer 8

the function is "increasing" means the derivative will be "positive" they are different concepts

Answer 9

so both derivatives of this function on this graph means that it f' is greater than 0 and f" is greater than 0? correct?

Answer 10

the number \(7\) is positive
the line \(y=7x+1\) is increasing, even when it is negative

Answer 11

as for the second derivative that is a different story
in this case the function is concave down, leaning to the left
that would be if you rode a bike along that path, you would be leaning it to the right
that makes the second derivative negative

Answer 12

State the signs of
f '(x)
and
f ''(x)
on the interval (0, 2). is the question..

Answer 13

this question would make more sense to me if it had a straight up function for me to derive it from

Answer 14

yes i see that
the function is increasing
that means \(f'>0\)

Answer 15

so to find the second derivative, you look at concavity as said above. I usually remember it as a smiley face. Smile is concave up and frown is concave down. If something is concave up its second derivative is positive, and if it's concave down the function's second derivative is negative.

Answer 16

the function is concave down (leaning left)
that measn \(f''<0\)

Answer 17

oops i meant "leaning right"

Answer 18

the concave down part is right, not very descriptive, but right

Answer 19

another way to describe it is "Is the function increasing at an increasing rate? or a decreasing rate" i.e. is it increasing faster or slower. Since you can see it is increasing, but coming to a stop it is increasing at less and less of a rate, so the rate of change of the rate of change must be negative

Answer 20

if it was increasing at an increasing rate, i.e. increasing faster and faster (thinking of a function like x^2 or e^x) then its second derivative is positive, because the rate of change of the rate of change is positive.

Answer 21

thats quite a few of "rates of changes" :) lol but as long as i can remember concave up is smile meaning positive and down is a frown which is negative.. that should help me out

Answer 22

Wish i could give out two medals to this.. i'd give you a medal too sylbot

Answer 23

I got another similar question I'm about to ask