Question

Need this explained please!

Find the first six terms of the sequence.

a1 = 6, an = 2 • an-1

Answer 1

just substitute 'n' with your number

Answer 2

so: an=2*6-1? @CrashOnce

Answer 3

ya so a2=2x6 -1
therefore a2 = 11

Answer 4

sorry thats a6

Answer 5

can you just rewrite it for me please? This is super confusing online!

Answer 6

@CrashOnce

Answer 7

a2=2*2-1=3
a3=2*3-1=5
a4=2*4-1=7
i think its like this may be wrong

Answer 8

@luigi0210

Answer 9

I'll try but what would I do with the 6? @CrashOnce

Answer 10

just want to clarify, is it \[a_n=2\times a_{n-1}?\]

Answer 11

yes! I didn't know how to write it like that.

Answer 12

it seems geometric sequence to me... where in the we have a common ratio between terms... and 2 is the common ratio between terms.... and the first term \(a_1=6\)

Answer 13

so \(a_2=2 \times 6 = 12\)

Answer 14

and \(a_3=2 \times 12=24\) and so on up to the 6th term...

Answer 15

so a4 would be 2*24=48?

Answer 16

yup...

Answer 17

Thank you so much!

Answer 18

no problem...