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Identify the 12th term of a geometric sequence where a1 = 8 and a6 = -8,192. 134,217,728 33,554,432 -33,554,432 -134,217,728
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If a1 = first term of a GP, then, nth term of the GP would be: \[\large{a_n = a_1 r^{n-1}}\] Here, r = common ratio
Now as @eric_d mentioned, \[\large{a_6 = a_1 r^{6-1} = a_1 r^5}\] Now, you know the value of a_6 and a_1 Using these values find out r.
The 12th term would be: \[\large{a_{12} = a_{1} r^{11}}\] You know a_1. Using the value of r you calculated above, find out a_12
oh okay give meh a sec.. :)
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Sure
ok I got the 3rd option
Correct
Good work :)
yay! thank you! :)
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Your welcome :)
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