Question

Integration.

Answer 1

what i did was i let u as 2y

Answer 2

i got 1/2 du = dy

Answer 3

is u sub not applicable to this problem?

Answer 4

Yeah, thats possible: Let u=2y, then du=2dy so the integral is now: (1/2) int[csc(u)du] = -ln|cot(u)+csc(u)|/2 + C = -ln|cot(2y)+csc(2y)|/2 + C

Answer 5

Please ignore my previous answer, this one should be the correct one if you do u substitution

Answer 6

the integral of csc(x) is known as - ln|csc x + cot x| + C and you should know it this way. If you even want to know how to get it, there is an example transformation here: http://math2.org/math/integrals/more/csc.htm. Maybe you can revise it, understand the logic, but i suggest you learn this formula

Answer 7

my answer was 1/2 ln l csc2y-cot2yl + c.. simplifying this further and i got the same answer as yours. =) Gee thanks!! =))

Answer 8

yea they're the same, ur welcome