Question

HELP MEEE!!!!
Solve the system of equations by determinants for z only:
2x+y=3z=-2
x-4y+z=24
-3x-y+4z=0

Answer 1

Ive found the original D and the \[D_z\]

Answer 2

I just dont understand the dividing part

Answer 3

@study100 can you help?

Answer 4

2x +y =3z =2?
is it
2x + y + 3z = 2

Answer 5

That's how it is on the paper, I also thought this was a typo, made by the professor. @study100

Answer 6

@study100 what do you think it might be?
cause it could be 2x+y-3z=2 OR 2x+y+3z=2

Answer 7

Yes that might be the case
but I think it's +3z, since the + and = are on the same key

Answer 8

yea lets just go with that

Answer 9

Now I have to form the quotient for D_z and D

Answer 10

but i'm not sure how to get that from this

Answer 11

2 1 3
D: 1 4 1
-3 -1 4

Answer 12

2 1 -2
D_z: 1 4 24
-3 -1 0