cot x sec^4 (x) = cot x + 2 tan x + tan^3 (x) how do i make these equal and please show all the steps because i want to know how to do this
What is sec^2 equal to?
isnt it 1+tan^2x
Right. So substitute that twice for sec^4 x.
ok
In other words you have (1 + tan^2s)^2 (and you still have to mutiply that by cot x; So expand (1+ tan^2)^2
so it would be (cotx)(1+tan^2x)(1+tan^2x)
Right, but multiply the 1+ tan^2x terms by each other. If you cannot figure that out, just expand (1+a)^2 and the substitute tan^2 for a when you are done.
ok now what
Then multiply by the cot x. And that should give you the answer.
? im confused
How so? Do you not know what (cot x)(tan x) is?
well this is what i have now (cotx)(1+tan^2x)(1+tan^2x)=cotx+2tanx+tan^3x
Isn't that what you were trying to prove?
yes
Well, you've done it.
i dont see how
\[ \large \begin{align} &\cot x \sec^4 (x) \cr &= (\cot x)(1+\tan^2x)(1+\tan^2x) \cr &= (\cot x)(1+2\tan^2x +\tan^4x) \ \cr &= \cot x+2\tan x +\tan^3x \end{align}\] That is what you did.
You took sec^4 x to be sec^2 x sec^2x, You substituted (1 + tan^2x) for each occurrence of sec^2 x. Then you multiplied the terms (1 + tan^2). Then you multiplied by cot x. Since cot x is the reciprocal of tan x, cot x canceled one tan x out of each term with a tan x.
ohhh ok i get it now
thanks
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