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Chemistry 7 Online
OpenStudy (superhelp101):

3. Assuming that is the identity of the metal, determine the percent error of your calculated specific heat capacity value.

OpenStudy (superhelp101):

@JoannaBlackwelder this is a follow up question to that, how do find the percent error? isn't it a formula?

OpenStudy (joannablackwelder):

http://www.mathsisfun.com/numbers/percentage-error.html

OpenStudy (superhelp101):

oh i see. so what is the approximate value?

OpenStudy (joannablackwelder):

The value you calculated.

OpenStudy (superhelp101):

oh so what about the exact value?

OpenStudy (joannablackwelder):

The value on the chart.

OpenStudy (superhelp101):

oh ok i will try to work it out then i will show you

OpenStudy (joannablackwelder):

ok :)

OpenStudy (superhelp101):

.208-.210/.208 they are in absolute value though

OpenStudy (joannablackwelder):

Check that. Be careful!

OpenStudy (superhelp101):

what numbers do i have to change?

OpenStudy (joannablackwelder):

It should be |approx-exact|/|exact| The numerator looks good, but check the denominator

OpenStudy (superhelp101):

oh i meant .210

OpenStudy (joannablackwelder):

Good. :)

OpenStudy (superhelp101):

i got it to equal .00952381

OpenStudy (joannablackwelder):

Sweet. :) Now, to put that into a percentage, multiply by 100%

OpenStudy (superhelp101):

.952381

OpenStudy (joannablackwelder):

%

OpenStudy (joannablackwelder):

:)

OpenStudy (superhelp101):

whee! Thank you for teaching me! :)

OpenStudy (joannablackwelder):

No worries :)

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