Question

HELP PLEASE!
The graph of the sine curve below is of electromagnetic energy that represents indigo light:

sine graph with points at 0, 0 and 107 and 5 tenths, 1 and 215, 0 and 322 and 5 tenths, negative 1 and 430, 0

What function accurately represents the sine curve for indigo light?

Answer 1

@barbillus do you think you can help me?

Answer 2

f(x) = sin 430πx

f(x) = sin 215πx

f(x) = sin pi over 215x

f(x) = sin pi over 430x

Answer 3

@abb0t @Abmon98 @Ashleyisakitty

Answer 4

@campbell_st i think its d am i wrong?

Answer 5

Thanks for helping me! :-)

Answer 6

well looking at the data, it takes the curve 430 units to complete 1 cycle...

so the period is

\[430 = \frac{2\pi}{B}\]

then the form of the equation is

\[y = Asin(Bx)\]

from the data the amplitude is 1

so its

\[y = \sin(Bx)\]

you need to find the period B using the information shown earlier in the post.

hope it helps

Answer 7

so is it 430? @campbell_st

Answer 8

no you need to find B knowing

\[430 = \frac{2\pi}{B}\]

you need to manipulate this equation to make B the subject

Answer 9

so its pi/430

Answer 10

@campbell_st

Answer 11

i mean pi/215?

Answer 12

thats correct... so its choice c or the 3rd one.

Answer 13

yay!! thanks! ;-)