Question

.What is the sum of a 6-term geometric series if the first term is 22 and the last term is 1,299,078?
1,395,030

1,461,460

1,527,890

1,594,320

Answer 1

@texaschic101

Answer 2

@zaibali.qasmi

Answer 3

@campbell_st

Answer 4

well you need to common ratio... before you find the sum.

the formula for a term is

\[a_{n} = a_{1} \times r^{n - 1}\]

so using what you know

\[1299078 = 22 \times r^5\]

you need to solve for r.

when you get r.

the sum of a geometric series is

\[S_{n} = \frac{a(1 - r^n)}{1 - r}\]

subsitute your values, n = 6, a = 22 and your r value to get the sum

Answer 5

Whoa, Whaat ;-;