Question

Find the 12th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.

Answer 1

.25

40

-348

72

Answer 2

@campbell_st

Answer 3

@vzfreakz

Answer 4

\(\sum_{i=1}^{12} (7i+22)=7\sum_{i=1}^{12}i+\sum_{i=1}^{12}22=7\left[\frac{12(13)}{2}\right]+12(22)\) <----I think that's what it would be.

Answer 5

Whao Whoa. ;-; Whoa. Wait. What. @YanaSidlinskiy

Answer 6

You've never seen this before?

Answer 7

Uh, No ;-;

Answer 8

This is algebra. Correct?

Answer 9

Yeah, Algebra 2 xD

Answer 10

Ok:) Wait..Does it look like this?

\(\sum_{i=4}^{15} \)
Btw, 15 should be on top and i-4 on bottom.

Answer 11

To actually calculate it, \(\sum_{i=4}^{15}( -2i-10)=-2 \sum_{i=4}^{15}i-\sum_{i=4}^{15}10\)

Answer 12

It looks like the drawing up there xD if yah scroll up ;3

Answer 13

ok, yea. I didn't really notice...but anyways...This is what it is:)
\(\sum_{i=4}^{15} (-2i-10)=-348\)

Answer 14

Oh thanks GURL :3 Can you help with a few more? ;o

Answer 15

Close this and open a new one.