Mathematics
6 Online
OpenStudy (anonymous):
f (x) = 3x + 6, g(x) = 2x2 Find (fg)(x
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OpenStudy (anonymous):
Any idea
OpenStudy (anonymous):
I think its 6x^2 +6
OpenStudy (anonymous):
Thanks for the free medal!
OpenStudy (anonymous):
And its wrong @Faith_123
OpenStudy (anonymous):
Then is it 6x^3 +12×^2
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OpenStudy (anonymous):
Wrong!!
OpenStudy (anonymous):
How do I solve this!?
OpenStudy (anonymous):
Not fair U took my medal!
OpenStudy (anonymous):
6x^2 +6 is correct! I was kidding
OpenStudy (jdoe0001):
\(\bf f (x) = 3x + 6\qquad g(x) = 2x^2
\\ \quad \\
(fg)(x)\implies f(x)g(x)\implies f(x)\times g(x)\implies (3x+6)\times (2x^2)\)
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OpenStudy (anonymous):
(Fg)(x)
OpenStudy (anonymous):
It's a multiple choice question and that's not one of the options @ KissMyAxe
OpenStudy (jdoe0001):
so what do you get if you multiply them over?
OpenStudy (anonymous):
First find `(fg)`which is `6x^2+ 6`
OpenStudy (anonymous):
than multiply this by 2x^2
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OpenStudy (anonymous):
Did u get it?
OpenStudy (anonymous):
Not really...
OpenStudy (anonymous):
(6x^2+ 6)*2x^2, now
OpenStudy (anonymous):
Yes but that gives you 12x^4 + 12x^2
OpenStudy (anonymous):
Yeah
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OpenStudy (anonymous):
Why u typing so slow
OpenStudy (anonymous):
That is not an option to this multiple choice question
OpenStudy (jdoe0001):
hmmm
OpenStudy (anonymous):
No idea than!
OpenStudy (jdoe0001):
\(\large \bf 6x^3 +12x^2\) is correct for (fg)(x)
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OpenStudy (jdoe0001):
unless you're expected to factor or such
OpenStudy (anonymous):
How did you get that answer?
OpenStudy (jdoe0001):
hmm? you got that answer yourself
" Then is it 6x^3 +12×^2 " <----
OpenStudy (jdoe0001):
so..how did You get it then?
OpenStudy (anonymous):
Where did i go wrong?
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OpenStudy (jdoe0001):
\(\bf f (x) = 3x + 6\qquad g(x) = 2x^2
\\ \quad \\
(fg)(x)\implies f(x)g(x)\implies f(x)\times g(x)\implies (3x+6)\times (2x^2)
\\ \quad \\
6x^3+12x^2\implies6x^2(x+2)\)
OpenStudy (anonymous):
OK that makes sense thanks