Question

What is the 6th term of the geometric sequence where a1 = −625 and a2 = 125?
@IMStuck

Answer 1

−0.2

0.2

−0.04

0.04

Answer 2

so.... what's the "common ratio" you think?

that is, the amount we multiplied the 1st term, to get the 2nd one?

Answer 3

Uh. ;-;

Answer 4

hmmm do you know what a geometric sequence is?

Answer 5

Yes.

Answer 6

so.... there's a multiplier to get to the 2nd term... so \(\large \begin{array}{ccllll}
-625& 125&...\\
&\uparrow \\
&-625\cdot {\color{brown}{ r}}
\end{array}\) so... what's that number "r' or ratio.... in order to get 125?

Answer 7

Uh. 1/5?

Answer 8

anyhow... to make it short.... the simpler way is just to keep in mind that \(\bf -625\cdot {\color{brown}{ r}}=125\implies {\color{brown}{ r}}=\cfrac{125}{-625}\)

Answer 9

For the Whole answer i got 0.2 :c Can yew check if im right?

Answer 10

I Kinda lost my calculator o-o

Answer 11

well \(\bf a_{\color{blue}{ 6}}=a_1\cdot {\color{brown}{ r}}^{{\color{blue}{ 6}}-1}\to -625\cdot {\color{brown}{ \left(\frac{1}{5}\right)}}^{5}\to -\cfrac{1}{5}\to -0.2\)

you're correct

Answer 12

https://desmos.com/calculator <--- btw

Answer 13

OH YAAAY. Can you help with a few more?

Answer 14

you can always post anew... so if I dunno.. someone else may and we can revise each other