Question

PLEASE HELP WILL MEDAL/FAN

Answer 1

@gahm8684

Answer 2

wait i got you

Answer 3

ok thanks

Answer 4

so do you know what to do @gahm8684

Answer 5

B is 12 if Im not wrong

Answer 6

so is price a is increasing. but by what percentage

Answer 7

what do you mean

Answer 8

give me a second, im solving c

Answer 9

when your done can you just tell me the answers for part a b and c

Answer 10

c is 0.44

Answer 11

or 0.430610365

Answer 12

so can you tell me one more time the answers for a b and c

Answer 13

im sorry man but the actual only one i could help you with was c >-<

Answer 14

@mathstudent55 @study100 @camerondoherty @sauravshakya @Fire_Fighter_Of_Miami @CGGURUMANJUNATH @ash2326 @thomaster @uri @HMT @nincompoop @myininaya @TSwizzle @iambatman @ikram002p @primeralph @myininaya @nincompoop @beccaboo333 @vlltimelow

Answer 15

please help guys

Answer 16

I am not good with math >_<

Answer 17

k

Answer 18

:(

Answer 19

can anyone help me

Answer 20

Set 16.13 = f(n)
take natural logs of both sides
ln(16.13) = ln (12 *1.03^n)
ln(16.13) = ln 12 + ln 1.03 ^n
ln (16.13) = ln 12 + (n) ln 1.03
n = ( ln 16.13 - ln 12) / ln 1.03
n= 10.006

So that's your maximum n, or days.
Starting at day 0, so domain is:
\[0\le n \le 10.006 \]

Answer 21

is that part a b or c

Answer 22

part A

Answer 23

part B
to find y intercept, set n = 0. Solve for f(n). Lemme know if you need more hints.

Answer 24

Part C: Average rate of change is:
\[\frac{ f(10)- f(3) }{ 10-3}\]
find f(10), f(3). Plug it in this equation to and find the final answer to rate of change.

Answer 25

wait so for part a the price is increacing by 10.006 percent a year

Answer 26

@study100

Answer 27

Hm? No. o.o
Not per year, that's why you need the domain.
Because the scientist ended his experiment at 16.13, n (which represents day) is 10.006 and can't not ever be bigger than that.

Answer 28

so he started from day 0 to day 10