Question

Solve the equation:
\[(2+\frac{ 3 }{ 2 })^2-(2+\frac{3 }{ x })-12=0\]

Answer 1

@dumbcow you mind helping me with this?

Answer 2

@dumbcow now any hints on how to solve this one? lol

Answer 3

try to isolate the "3/x"

2+ 3/2 = 7/2

Answer 4

\[(\frac{7}{2})^2 -12-2 = \frac{3}{x}\]

Answer 5

so then its \[\frac{ 49 }{ 4 }-12-2=\frac{ 3 }{ x }\]

Answer 6

which equals
\[\frac{ -7 }{ 4 }=\frac{ 3 }{ x }\]

Answer 7

correct ... cross-multiply and solve for x

Answer 8

x=-12/7?

Answer 9

yep

Answer 10

alright thanks man

Answer 11

:)

Answer 12

and i just noticed im an idiot -_-

Answer 13

lol the beginning (2+3/2)^2 is (2+3/x)^2

Answer 14

\[(2+\frac{ 3 }{ x })^2-(2+\frac{ 3 }{ x })-12=0\]

Answer 15

yeah i was afraid of that... i should have said something

ok its not hard just make a substitution
let u = 2 + 3/x

--> u^2 - u - 12 = 0
solve for u