Question

some one please help

Answer 1

only part c

Answer 2

please help @jdoe0001

Answer 3

well... if you have part B done... then.... is just a matter of plugging in the years, or 20 into it

Answer 4

well part b answer is "2. it is non-linear because the difference in the amount between two successive years keeps increasing."

Answer 5

but can you show me the steps with the answer for part c please

Answer 6

hmmm part B is supposed to be the function itself

Answer 7

part C depends on part B

Answer 8

well can you help me with both parts then i guess please

Answer 9

well... have you got part A yet?

Answer 10

part A is "Option 1 is linear because for each year the amount increases by the same amount of $100."

Answer 11

? of 100? for option 1? notice the table a bit closer
keep in mind that she starts off with $1,000

Answer 12

can you then please explain all parts a part a b and c? i would really appreciate it

Answer 13

well... look at the values in option say 2

she starts off with \(\large \begin{array}{ccllll}
years&amount
\\\hline\\
0&1,000\\
1&1,300\\
2&1,600\\
3&1,900
\end{array}\) so... what do you think? how much is it increased by yearly? is there a pattern?

Answer 14

300

Answer 15

so... she's gettting 300 more, every year
any ideas on the equation for that?

Answer 16

so the answer for part a is "Option 1 is linear because for each year the amount increases by the same amount of $300."

Answer 17

it'd be,yes

Answer 18

how about part b

Answer 19

well... what do you think would be the equation for option 1? the 300 one

Answer 20

idk

Answer 21

can you just show me how you find it

Answer 22

let's say, we want to find how much Belinda has today
we know how much she had last year

so... let's say she had "P" amount last year
how much would she have this year with option 2?

Answer 23

We can make the assumption the interest is compounded annually for option 2 and use the compound interest formula and see if we can find an equation:
A=P(1+rn)nt
. Here n = 1 (if compounded yearly) and so A = P(1+r)^t

Answer 24

P = 1000 A = 1000(1 + r)^t t = 1, A = 1100 1100 = 1000(1+r)^1 1+r = 1100/1000 = 1.1 r = 1.1 - 1 = 0.1 Let us see if this will work for t = 2 A = 1000(1.1)^t when t = 2 A = 1000(1.1)^2 = 1210 (which agrees with 1210 for year 2) Let us try t = 3: A = 1000(1.1)^3 = $1331 (agrees with year 3) So the function for option 2 is: f(n) = 1000(1.1)^n

Answer 25

i found this on the internet. is this suppose to do anything with part B

Answer 26

For option 1) f(n) = 100n + 1000

Answer 27

well... I don't thiink is annually compounded, so that'd be if the quantity were compounded annually

Answer 28

this is so confusing. can you please show me the steps with answers please my online homework is about to end in 6 minutes

Answer 29

well... the steps are there already in the material.... get the linearity of the values, get the equation for it, and then plug in 20 in the equation, see which one gives the greatest amount in 20 years

Answer 30

@jdoe0001

Answer 31

@study100 can you help me with part b and c please im in a hurry

Answer 32

please help with part b and c

Answer 33

Part B: option 2 = C + 300n while C= 1000, so plug in

Answer 34

2=1000+300n

Answer 35

is that right

Answer 36

@study100

Answer 37

Hm
f(n) = 1000 +300 n for option 2

Option 1
f(n) = 1000 (1.3)^n

Answer 38

I took 1690 /1300
equals to 1.3

Answer 39

Now that you have the equation for option 1 and 2
plug n=20 for each equation to compare which one is greater.

Answer 40

option 1 : f(n) = 1000 (1.3)^n
option 2: f(b) = 1000 + 300n
plug in n you have
f(20)= 1000 (1.3)^20
f(20) = 1000 + 300(20)

then compare

Answer 41

Hm it seems like I can't message you ;u; am I blocked?

Answer 42

no

Answer 43

why cant you message me what does it say cause i didnt block you.here ill take a picture for proof

Answer 44

look at the picture i didnt block you

Answer 45

so can you please give me the answers please. my time is over but i could still get half credit, please give me the answers

Answer 46

Part B: option 1 : f(n) = 1000 (1.3)^n
option 2: f(b) = 1000 + 300n

Part C:plug in n you have
f(20)= 1000 (1.3)^20
f(20) = 1000 + 300(20)

then compare:
Answers
option 1: 190049.64 dollars
option 2: 7000 dollars.
option 1 is the better choice

Answer 47

@study100 do i have to pick a option or do i write them all down like you put them?

Answer 48

Part B, write all
Part C: write things below "Answers"
but next time I hope you have more time working these out so you understand them.