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Mathematics 6 Online
OpenStudy (anonymous):

Which of the following equations have the same solution? Solve all three equations separately, and explain each step.

OpenStudy (anonymous):

OpenStudy (anonymous):

@beccaboo333 @mathstudent55 @jdoe0001 @jim_thompson5910

OpenStudy (anonymous):

I Been @Practice From 6 To 12 And Been On Online HS Since Its 8pm :'( PLEASE JUST ANSWER #3 COMPLETELY BY EVERY STEP SO I CAN FINISH !

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

@half

OpenStudy (anonymous):

@xBeEnchantedx PLEASE HELP!

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

@xBeEnchantedx FINALLY A Reply Thank u!

OpenStudy (anonymous):

I Only Need Help With 3

OpenStudy (anonymous):

...

OpenStudy (xbeenchantedx):

\[\frac{ x-2 }{ 5} = \frac{ 4x+2 }{ 25 } \] First, multiply both sides of the equation by (5)(25). By doing this, you are cancelling the denominator. \[(5)(25)\frac{ x-2 }{ 5 }=\frac{ 4x+2 }{ 25 } (5)(25)\] 25(x-2) = 5(4x+2) Then simplify the equation by distributing 25 into (x-2) and 5 into (4x+2). 25x-2=20x+2 Lastly, solve for x by adding 20x to both sides of the equation to cancel out 20x and -2 to both sides of the equation to cancel out -2. 5x=4 Then divide both sides by 5 to isolate x and you'll end up with x=4/5.

OpenStudy (anonymous):

THANK!! YOU IF I HAD A MEDAL I WOULD GIVE IT TO YOU!

OpenStudy (xbeenchantedx):

No problem :) Make sure you check the answer by plugging in x=4/5 into the original equation.

OpenStudy (xbeenchantedx):

OMG HOLD ON

OpenStudy (xbeenchantedx):

There's a little mistake you might've caught. I'm sorry, I can't do math in my head X) But when distributing, I forgot to distribute the outside term to every term on the inside of the parenthesis. So you're supposed to get 25x-50=20x+10 Which gives you x=12 when you simplify.

OpenStudy (xbeenchantedx):

I am so sorry I got that small part wrong. When I worked it out on paper and checked my answer, I realized my original answer was wrong. Now when you check x=12 it will FOR SURE be correct.

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