Question

Balance these equations:
(a) ____Fe(s) + ____S(s)h____Fe2S3(s)
(b) ____P4(s) + ____H2(g)h____PH3(g)
(c) ____NO(g) + ____Cl2(g)h____NOCl(g)
(d) ____SiCl4(l ) + ____Mg(s)h____Si(s) +____MgCl2(s)
@JoannaBlackwelder

Answer 1

I have NO CLue how to do this

Answer 2

For a, you have 1 Fe and 1 S on the left side of the reaction and 2 Fe's and 3S's on the right. Do you see how I got that?

Answer 3

@beccamarx19?

Answer 4

no

Answer 5

Fe means 1 atom of Fe or iron and S means 1 atom of S or Sulphur.

Answer 6

But Fe2S3 means a compound that contains 2 atoms of Fe and 3 atoms of S.

Answer 7

Does that help?

Answer 8

ok
what is h?

Answer 9

I think that should be the symbol for the reaction. It should look more like this ->
I'm not sure why yours shows up as an h.

Answer 10

yep you are right, ok can you help me with the rest of these I have like 20 other problems like like one

Answer 11

I can, but we haven't finished this one yet.

Answer 12

i mean this full question

Answer 13

So, we need to add coefficients to make the numbers of atoms equal on each side.

Answer 14

So, we need to put a 2 in front of the Fe to make it equal on both sides.

Answer 15

And a 3 in front of the S. Make sense?

Answer 16

yes

Answer 17

Make a table like the one I am about to show you.

Answer 18

Awesome! :) Can you try the next one?

Answer 19

To be balanced, both sides must match! Meaning, there should be 2 iron and 3 sulfer on ractant side.

Answer 20

____P4(s) + ____H2(g)h____PH3(g)= 1P4(s)+1H(g)h 4PH3(g)?

Answer 21

@JoannaBlackwelder

Answer 22

Balance it.

Answer 23

abbot i do not understand your charts thankyou

Answer 24

You made the P's match. How about the H's?

Answer 25

____P4(s) + ____H2(g)h____PH3(g)= 1P4(s)+1H2(g)h 4PH3(g)?

Answer 26

@JoannaBlackwelder is doing a fine job, but she is also doing the same thing I am, without the chart.

Answer 27

Thanks @abb0t :) You are right.

Answer 28

i do not understand the charts

Answer 29

You don 't have to, @beccamarx19. :)

Answer 30

You have 2 H's in the reactants and 12 in the products.

Answer 31

i give up

Answer 32

Don't give up! Just add a 6 in front of the H2 in the reactants and you are done. :)

Answer 33

huh?

Answer 34

is 2 H's

Answer 35

If you put then you have 4 H's. Make sense?