Question

what is the quotient 6-x/x^2+2x-3 divided by x^2-4x-12/x^2+4x+3

Answer 1

@mathstudent55 @JoannaBlackwelder

Answer 2

Have you considered factoring things?

Answer 3

@tkhunny I don't know what to do at all. Can we walk through it? And should I post the answer choices?

Answer 4

yeah post the answer choices it always narrows it down

Answer 5

You walk through it.

Factor these:
6-x
x^2+2x-3
x^2-4x-12
x^2+4x+3

Answer 6

How do I factor them?

Answer 7

What class are you in?

Answer 8

x^2+4x+3 factored would be (x-1) (x-3) right?

Answer 9

6-x (x-6)
x^2+2x-3 (x+3) (x-1)
x^2-4x-12 (x+2 (x-6)
x^2+4x+3 (x-1) (x-3)
@tkhunny

Answer 10

tkhunny just comes and goes..0.0

Answer 11

Am I even right?

Answer 12

I'm confused.

You say this: "How do I factor them?"

Then you pop out with this:

"6-x (x-6)
x^2+2x-3 (x+3) (x-1)
x^2-4x-12 (x+2 (x-6)
x^2+4x+3 (x-1) (x-3) "

So, you DID know how to do it? Why were you declining?

Perfect. Now, rewrite that horrible original fraction in terms of these factored versions.

Answer 13

(x-6)/(x+3)(x-1) divided by (x+2) (x-6)/(x-1)(x-3)

@tkhunny

Answer 14

Nice. Now, utilize the idea of division of fractions (reciprocal and multiply) and rewrite it again.

Answer 15

Wait. What does that mean? I've completely lost everything. @tkhunny

Answer 16

Calculate the quotient: \(\dfrac{\dfrac{1}{3}}{\dfrac{9}{5}}\).

Answer 17

5/27 @tkhunny

Answer 18

How did you determine that?

Answer 19

I used a fractions calculator

Answer 20

{sigh} That doesn't help. You should know how to divide fractions.

\(\dfrac{\dfrac{1}{3}}{\dfrac{9}{5}} = \dfrac{1}{3}\cdot\dfrac{5}{9} = \dfrac{5}{27}\)

Have you seen the process usually called "reciprocal and multiply"? That is all we are doing.

Answer 21

I got 5/27?... And no. This unit was one of the hardest units I've ever done.

Answer 22

You don't seem to be answering my questions. You have not yet responded to the concept of "reciprocal and multiply". HAVE you seen it or heard of it? It is the way to divide fractions.

(2/5) / (1/7) = (2/5)*(7/1)

That has to look familiar.

Answer 23

I obviously responded to your question when I said "And no". It looks semi familiar but I don't remember working it like that at all.

Answer 24

It's time for you to do it with the giant expression.

(x-6)/[(x+3)(x-1)] divided by [(x+2) (x-6)]/[(x-1)(x-3)]

Answer 25

x^2+4x+3= (x+1) (x+3)

Answer 26

Please check this factorization

Answer 27

Sorry. I got busy. The answer I got was 1/(x-3)(x-1)^2(x+2)(x+3)

Answer 28

its wrong
option 3 is correct

Answer 29

So its C. Can you help me with another? @bradely

Answer 30

simplify the complex fraction x/x+4/1/x+1/x+4

Answer 31

Now how do I do this one? :P

Answer 32

i will respond u

Answer 33

Okay. Thanks

Answer 34

Option 4 is correct please check in site

Answer 35

I saw it! Thanks man. You're rad B)