Question

-z^2+6=-5z

Answer 1

If you add 5z to both sides you will get your expression in the quadratic form,
\[-z^2+6 = - 5z\]
After adding 5z to both sides we now have:
\[-z^2+6 + 5z = 0\]
If we rearrange the 5z and 6 we get:
\[-z^2+5z+6 = 0\]

This is now in the quadratic form:
\[ax^2+bx+c = 0\]

For which you can use the quadratic formula to solve for the roots:
\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 2

can you explain to me how to do quadratic form?

Answer 3

If you compare them you see that we have,

a = -1
b = 5
c = 6

Using those we can put them into our quadratic formula and we will have:
\[\frac{ -5 \pm \sqrt{(5^2)-4(-1)(6)} }{ 2(-1) }\]

Answer 4

then do i solve that?

Answer 5

Yes

Answer 6

okay, thank you!

Answer 7

It depends on the final answer you are asked for but yes you should solve that and it will give you the roots of your problem.

My pleasure.