Which is a rational number?
I think 8 might not be it
A rational number is one which can be written as a ratio of integers. Example: \(\Large\rm \sqrt9\) is rational because \(\Large\rm \sqrt{9}=3\) And \(\Large\rm 3\) can be written as a ratio of integers \(\Large\rm \frac{3}{1}\).
where denominator is not 0.
If we look at for example \(\Large\rm \sqrt{8}\), we can simplify this a little bit by writing it as \(\Large\rm \sqrt{4\cdot2}=\sqrt{4}\cdot\sqrt{2}=2\sqrt{2}\) We were able to a perfect square out of it, but see how there is still a 2 stuck inside? There is no fraction involving integers that represents sqrt(2), so that part of the number makes it irrational.
To simplify, if you're taking the square root of anything except a perfect square, then it is `irrational`.
So yes, you're correct, 8 is not the right answer c:
Do you understand how to find the correct option now? Which square root gives you an integer solution?
Is it 16 cause it looks like a perfect square
Yes, good job!
Rational: \[\Large\rm \sqrt{16}=4=\frac{4}{1}\]
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