Question

could U Help me Guys ??

Answer 1

Maybe. What's your question?

Answer 2

\[\prime \cos(3x) ^2 \]

Answer 3

Is this your exact question? https://www.wolframalpha.com/input/?i=cos%283x%29%5E2&lk=4&num=2&lk=4&num=2

Answer 4

Try that :). And make out whatever it is saying. I just typed it into the wolfram calculator

Answer 5

\[F(x)\prime = (\cos(3x)^2)\prime ??\]

Answer 6

Ohh. Okay. I couldn't see all of it at first. Let me renter. Can you just type it as a text?

Answer 7

Hey. Instead. Just go to Wolfram Calculator and enter the question yourself and see what comes up https://www.wolframalpha.com/

Answer 8

Soit la Fonction Définie par \[f(x) = \cos(3x)^2 \] . On cherche la valeur de \[F \prime(\pi/4) : \] ???

Answer 9

?????

Answer 10

Did you post it on the calculator? https://www.wolframalpha.com/ and see what it says?

Answer 11

Here's your first one. Entered https://www.wolframalpha.com/input/?i=f%28x%29%3Dcos%283x%292

Answer 12

thats it ... d/dx(cos^2(3 x)) = -3 sin(6 x) ;) Thank U Friend ;)

Answer 13

but the Probleme I need To Know the etap ... !! :(

Answer 14

Yeaaaaah ... I Know It by my Self ... We past with this Property ...
cos(3X)^2...we Must change To.. . 1+cos(2∗3X)/2 and after we do the F′...Its Sooo Easyy..;)

Answer 15

You're welcome bud. Good luck in your studies :)

Answer 16

want help from a harvard student ?