Couple of Trig Questions http://prntscr.com/47dqu3
The angle that you have in radians is equal to 105 degrees. Since my mind works better in degrees, I converted it, and found that the angle lie in QII with a coterminal angle of 75 degrees. That is a 45 degree angle plus a 30 degree angle, so you could use tan(A+B) to find the exact value of that angle. Do you know that identity? It is a sum identity.
\[\tan(45+30)=\frac{ \tan(45)+\tan(30) }{ 1-\tan(45)\tan(30) }\]
Let's look at what the tangent of 45 and the tangent of 30 are.
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Now we can easily do the math using those values. We will get an exact value of what you're looking for that way.
\[\tan(45+30)=\frac{ 1+\frac{ \sqrt{3} }{ 3 } }{ 1-(1)(\frac{ \sqrt{3} }{ 3 }) }\]
FOllowing.
So just simplify that, and I'm done?
Yes, I'm doing that now...wasted a ton of time with the drawing tool then realized I was running out of room and it looked like a mess, so I'm writing it out by hand. Try it and let me know what you get. I will post in a sec...rationalizing denominators right now...
Ok, I'm going to do it again...
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