Compare the functions shown below: f(x) = 2 sin (3x + π) − 2 g(x) = (x − 3)2 − 1 h(x) x y -2 3 -1 -2 0 -5 1 -6 2 -5 3 -2 4 3 Which function has the smallest minimum y-value?
@Abhisar
What's h(x)
h(x)
h(x) is the answer////
how?
What is the minimum of f(x)?
-2?
nope its has the minimum when sin(3x+pi) is minimum
minimum of sin(3x+pi) is -1 ok?
but where did you get -1
any sin value can only exist between +1& -1 ok?
so +1 is maximum and -1 is minimum?
yes so can you now tell the minimum of f(x)?
By studying the behavior of the sin graph. The graph is stretched by a vertical factor of 2 (meaning it oscillates from -2 to 2) and then by seeing that the -2 at end brings it down 2 units. So now it oscialltes from -4 to 0 so the min of that graph is -4, you forgot about the 2 in fron and the 2 being subtracted @amilapsn https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=2sin(3x%2Bpi)-2
-1
The min of f(x) is -4
nope it's -4
no!!!!!!!!! im so confused
minf(x)=2(-1)-2, when plugging -1 to sin(3x+pi)
then the minimum of g(x) would be -2?
f(x): https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=2sin(3x%2Bpi)-2 Min of -4 g(x) https://www.google.com/search?q=(x+%E2%88%92+3)2+%E2%88%92+1&oq=(x+%E2%88%92+3)2+%E2%88%92+1&aqs=chrome..69i57&sourceid=chrome&es_sm=0&ie=UTF-8#q=(x+%E2%88%92+3)%5E2+%E2%88%92+1 Min of -1 h(x): By looking at the ordered pairs, the smallest y value is -6 so you can conclude that -6 is smaller than -4 and -1 (which are the mins of the other two functions)
no it's -1
how i thought you have to do 1(-1) - 1
am i not right?
no here we have to consider about,\[(x-3)^2\]
ok...
What do you think the minimum of \[(x-3)^2\]
-1
for any real x it will have a positive value except for...
x=3
ohhh ok
So what is the minimum of h(x)?
yeah thanks
but can i post another one for practice?
-6
OK..
Though this isn't the same problem, figured I'd post it here:
This was the prob: Which function has the smallest minimum? All three functions have the same minimum f(x) g(x) h(x)
Ok, can you do it?
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