Question

how do i get the derivative of these two:
*2e^θ
*e^-θ/2

Answer 1

Take note that \[\frac{ d }{ dx }(e^x) = e^x\]
Therefore,
\[\frac{ d }{ d \theta } (2e^\theta) = 2e^\theta\]

Answer 2

And
\[\frac{ d }{ d \theta } (e^-\frac{ \theta }{ 2 })= \frac{ -1 }{ 2 } (e^\frac{ -\theta }{ 2 }) \]

Answer 3

Thanks!!