What volume of 1.25 M sodium hydroxide (NaOH) solution can be prepared using 60.0 g of sodium hydroxide? (The mass of one mole of NaOH is 40.0 g.)
Answer

0.667 L

0.833 L

1.20 L

1.88 L

Question

What volume of 1.25 M sodium hydroxide (NaOH) solution can be prepared using 60.0 g of sodium hydroxide? (The mass of one mole of NaOH is 40.0 g.)
Answer
		
0.667 L
		
0.833 L
		
1.20 L
		
1.88 L

anonymous · Answer

@abb0t

abb0t · Answer

I'm sorry, I have to leave soon, but maybe @ganeshie8 could help you or know someone who is online and can. All the best.

abmon98 · Answer

Number of moles=Mass(g)/Molar Mass(g/mol)
Number of moles=Concentration(mol/dm^3)*Volume(dm^3)
60/40=3/2 moles of NaOH
(1.5)/1.25

anonymous · Answer

1.2 is correct then?
Also, thnx for your response @abb0t :)

anonymous · Answer

I had already selected 1.2, but wasn't sure..

abmon98 · Answer

yes its 1.2

anonymous · Answer

gratzi!! :D