\[3x+y=3\]
\[x-y=5\]
u can start with elimination anything x or y
so if u eliminate x then from the second eq. u can write
\[x=y+5\]
now put this in the first eq. in place of x
\[3(y+5)+y=3\]
now solve for y
OpenStudy (texaschic101):
nicely explained :)
OpenStudy (sidsiddhartha):
thank u @texaschic101
OpenStudy (texaschic101):
just telling the truth....I give credit where credit is due :)
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OpenStudy (sidsiddhartha):
:)
OpenStudy (sidsiddhartha):
hay @Grim4
now can u solve it?
OpenStudy (anonymous):
y=-3
OpenStudy (sidsiddhartha):
yeah y=-3
now can u find out x
OpenStudy (texaschic101):
3(y + 5) + y = 3
3y + 15 + y = 3
3y + y = 3 - 15
4y = - 12
y = -3
yep...now sub -3 back into either equation to find x
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OpenStudy (anonymous):
x= -8
OpenStudy (anonymous):
Now that I think about it i think that might be wrong o_O
OpenStudy (sidsiddhartha):
remember the second equation
\[x-y=5\]so
\[x=y+5\]
now put y=-3
OpenStudy (anonymous):
It's 2
OpenStudy (sidsiddhartha):
yup correct :)
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