The graphs of functions f(x) and g(x) = f(x) + k are shown below:
The value of k is ___. Numerical Answers Expected!
g(x) is f(x) but has been vertically shifted. Measure from the left side of the line. The old line started where? The new line now starts where?
would it be -2
You have the correct value, but wrong `sign`. The k forced g(x) to move `upward`. So we want a positive 2.
Thank you I have one more can you help
sure
Choose the equation below that represents the line passing through the point (-5, 1) with a slope of three halves. y - 5 = three halves(x + 1) y + 1 = three halves(x - 5) y + 5 = three halves(x - 1) y - 1 = three halves(x + 5)
The point-slope form of a line is: \(\Large\rm y-y_o=m(x-x_o)\) Where \(\Large\rm (x_o,y_o)\) is the given point. and \(\Large\rm m\) is the slope.
So just plug those values in! :)
would it be the 4th answer
Yes, good job!
I need help with one more before I go, can you help.
class starting soon, i might have to go, but ya i can try to help.
The graph below plots a function f(x):
If x represent time, the average rate of change of the function f(x) in the first three seconds is ___. Numerical Answers Expected!
slope m =3/2 point (-5,11) (y-1)=(3/2)(x+5) option 4 is correct
I think the answer is 80
So at 3 seconds, the y-value is 220. At 0 seconds, the y-value is 100. If we write these as ordered pairs, \(\Large\rm (0,100)\), \(\Large\rm \qquad (3,220)\) We can use the slope formula to find the rate of change, \(\Large\rm m=\dfrac{y_2-y_1}{x_2-x_1}\)
80? Hmm, I'm coming up with something smaller.
what about 60
Now it feels like you're just guessing -_- Plug in the numbers, calculate the slope :3
\(\Large\rm m=\dfrac{220-100}{3-0}\)
I divide by 3
120/3 = 40 i think, yes.....?
Thank You
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