Question

@camerondoherty @Its_A_Moot_Point @lacrosseplayer22 @mathstudent55 @Sheraz12345 @SolomonZelman @study100 @anteater @sidsiddhartha

Answer 1

ok then the first thing that you should go is put the two first equations into standard form, which is y = mx + b

Answer 2

so the first equation will be y = -2x + 6 the second equation will be
y = -2x + 4

Answer 3

\[2x+y=6................(1)\]
and
\[6x+3y=12................(2)\]
from the second equation take 3 common then it will become
\[3[2x+y]=12\rightarrow 2x+y=4\]

Answer 4

then you graph. for the first equation you graph the 0,4 and then you rise 2, and go right 1

Answer 5

plot that point and you have your first line.

Answer 6

same process for the first one

Answer 7

so look those two equations are same with different intersecting values
so they are parallel lines

Answer 8

so number 3 is C. but how about number 4

Answer 9

if u see two lines like this---\[ax+by=c\]and
\[ax+by=d\]
then ur immediate conclusion will be----lines are parallel

Answer 10

nope its B-parallel lines

Answer 11

ok but how about number 4

Answer 12

try eliminating y by putting
y=x+3 inplace of y in second equation
\[4x+x+3=18\rightarrow 5x=15\rightarrow x=3\]
and now put x=3 in the first eq.
u'll get
y=3+3=6
so
x=3
y=6

Answer 13

number 3 is b
number 4 is b right?

Answer 14

yeah right
but did u understand the solution

Answer 15

yes thank you