Brian is creating a collage on a piece of cardboard that has an area of 120r3 square centimeters. The collage is covered entirely by pieces of paper that do not overlap. Each piece has an area of the square root of r to the fifth power square centimeters. Use the given information to determine an expression for the total number of pieces of paper used. Someone please help me :)
So the overall area is \(\Large 120r^3\) ? and each piece has an area of \(\Large \sqrt{r^5}\) ?
Yess
let x = number of pieces needed
if you have x pieces, each of area with \(\Large \sqrt{r^5}\) square units then you'll have \(\Large x*\sqrt{r^5}\) as the total area
So therefore, \[\Large x*\sqrt{r^5} = 120r^3\] solve for x to get ???
Okay so I'm confused on how to solve for x
you divide both sides by sqrt(r^5), then rationalize the denominator like this \[\Large x*\sqrt{r^5} = 120r^3\] \[\Large x = \frac{120r^3}{\sqrt{r^5}}\] \[\Large x = \frac{120r^3*\sqrt{r^5}}{\sqrt{r^5}*\sqrt{r^5}}\] \[\Large x = \frac{120r^3*\sqrt{r^5}}{\sqrt{(r^5)^2}}\] \[\Large x = \frac{120r^3*\sqrt{r^5}}{r^5}\] \[\Large x = \frac{120r^3*\sqrt{r^{4+1}}}{r^5}\] \[\Large x = \frac{120r^3*\sqrt{r^{4}*r^{1}}}{r^5}\] \[\Large x = \frac{120r^3*\sqrt{r^{4}}*\sqrt{r}}{r^5}\] \[\Large x = \frac{120r^3*r^{2}*\sqrt{r}}{r^5}\] \[\Large x = \frac{120r^{3+2}*\sqrt{r}}{r^5}\] \[\Large x = \frac{120r^{5}*\sqrt{r}}{r^5}\] \[\Large x = 120\sqrt{r}\]
Okay...so would the answer be that equation or what? I'm awful at this stuff
well they want an expression, ie this \(\Large 120\sqrt{r}\) because that represents the exact number of pieces needed
because we said "let x = number of pieces needed"
So is the answer 120 sqrt. r?
correct
and those steps show why/how
Okay so if i write all of that above and then make my final answer 120 sqrt. r thats it?
yes pretty much
Thank you so much!
you're welcome
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