Question

Segment AB has point A located at (4, 2). If the distance from A to B is 3 units, which of the following is the coordinate for point B?

Answer 1

(5, 2)

(1, 5)

(4, -1)

(-2, 2)

Answer 2

@paki Can you help?

Answer 3

@hanner_B_nanner @Orion1213

Answer 4

@camerondoherty

Answer 5

distance formula will do...

Answer 6

idk how to apply it

Answer 7

\[d=\sqrt{(x_2-x_1)^2+(y_2-2_1)^2}\]

Answer 8

d=3 units and point A (4,2) is given...

Answer 9

is it -2,2

Answer 10

we can check by plugging in the values...

Answer 11

\[d=\sqrt{(4-(-2))^2+(2-2)^2}=\sqrt{(6)^2+0}=\sqrt{36}=6~units\]therefore it is not the correct answer....

Answer 12

... wait i'm recalling another formula in solving this problem...

Answer 13

oh ok...

Answer 14

1,5 maybe

Answer 15

it is 4,1... 'cause \(d=\sqrt{(4-4)^2+(2-(-1))^2}=\sqrt{0+9}=3\) units...

Answer 16

i'm sorry, it should be (4,-1)...

Answer 17

thanks :) can you help w another ? @Orion1213

Answer 18

ok...

Answer 19

Find the perimeter of a quadrilateral with vertices at C (−2, 4), D (−3, 1), E (1, 0), and F (−1, 2). Round your answer to the nearest hundredth when necessary.


10 units

10.77 units

11.52 units

12.35 units

Answer 20

@Orion1213

Answer 21

10.77?

Answer 22

@Orion1213

Answer 23

\[d_{CD}=\sqrt{(-3-(-2))^2+(1-4)^2}=\sqrt{1+9}=\sqrt{10}\]
\[d_{DE}=\sqrt{(1-3)^2+(-2-(-1))^2}=\sqrt{4+1}=\sqrt{5}\]
\[d_{EF}=\sqrt{(-1-1)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}\]
\[d_{FC}=\sqrt{(-2-(-1))^2+(4-2)^2}=\sqrt{1+4}=\sqrt{5}\]
\[P_{CDEF}=\sqrt{10}+\sqrt{5}+\sqrt{8}+\sqrt{5}=10.46~units\]
think you're right... maybe it's my round off....