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Mathematics 15 Online
OpenStudy (anonymous):

What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x - π) from x = 0 to x = 2π

OpenStudy (anonymous):

Easiest way to do this is to graph.

OpenStudy (anonymous):

That's not a bad idea, lemme try

OpenStudy (anonymous):

I recommend https://www.desmos.com/calculator

OpenStudy (anonymous):

Will it give periods in terms of the radians like the problem?

OpenStudy (anonymous):

It didn't, and I need that : /

OpenStudy (anonymous):

You don't really need them, just look at the points from x = 0 to around 6.28

OpenStudy (anonymous):

You need to determine the critical numbers for the function and the values at the end points.

OpenStudy (anonymous):

I'm so confused @nelsonjedi @ridoleor

OpenStudy (anonymous):

The critical points are the points where the tangent line to the function are flat (no slope)..You have to determine the derivative of the function first as this will allow you to determine where on the graph your slope is flat or equals 0.

OpenStudy (anonymous):

@nelsonjedi would the answer be 3pi / 2 and pi? please i'm desperate and running out of time :/

OpenStudy (anonymous):

What are your choices?

OpenStudy (anonymous):

The x coords would be pi/2 and 3pi/2.

OpenStudy (anonymous):

@ridoleor @nelsonjedi that's one of the choices so i'll go with that. thank y'all so much it means a lot.

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