F****** Trig... http://prntscr.com/47ndt0

Question

jdoe0001 · Answer

hmm do you know what an inverse trig function means?   that is,..... what does $\bf \large csc^{-1}$ mean?

anonymous · Answer

The inverse of csc.

anonymous · Answer

SO the inverse of 1/sin? @jdoe0001

jdoe0001 · Answer

well.. yes.... but ... hmm   anyhow.... it means    "what is the angle WHOSE csc() is whatever value"

jdoe0001 · Answer

so $\bf y=csc^{-1}(-1)\implies y=\cfrac{1}{sin^{-1}(-1)}$   so

what is the angle then, WHOSE sine is -1?

anonymous · Answer

270

jdoe0001 · Answer

270 degrees.. yes   thus $\bf y=csc^{-1}(-1)\implies y=\cfrac{1}{sin^{-1}(-1)}
\implies y=\cfrac{1}{270^o}$

now if you wish to use the radian unit, then that'd be $\bf y=csc^{-1}(-1)\implies y=\cfrac{1}{sin^{-1}(-1)}
\implies y=\cfrac{1}{\frac{3\pi}{2}}\to \cfrac{2}{3\pi}\to \cfrac{2}{3}\pi$

ikram002p · Answer

i thought its f for real lol 
damn its not even close to that :P

anonymous · Answer

2/3π isn't an option...

jdoe0001 · Answer

hmmm    right.... lemme I find something funny theee hehh

anonymous · Answer

Let me know...

ikram002p · Answer

http://www.wolframalpha.com/input/?i=csc^-1+-1

jdoe0001 · Answer

one sec

anonymous · Answer

Thanks, Ikram. and jdoe!

jdoe0001 · Answer

hmmm