Question

This is harddd...

Answer 1

The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 2 to t = 5 represent?

The ball travels an average distance of 112 feet from 2 seconds to 5 seconds.

The ball falls down with an average speed of 48 feet per second from 2 seconds to 5 seconds.

The ball falls down with an average speed of 112 feet per second from 2 seconds to 5 seconds.

The ball travels an average distance of 48 feet from 2 seconds to 5 seconds.

Answer 2

\[d(t) = 16 t^{2}\]
is that the equation?

Answer 3

yep :)

Answer 4

doesnt the and the 2 cancel out?

Answer 5

*5

Answer 6

oh hold on, it doesn't ask you what is the average rate of change.
In this case,

the average rate of change means how fast the height of the ball is changing.

Answer 7

yes but dont you need to like solve something?

Answer 8

d(5) = 16 (5)^2 = 16 *25 = 400
d(2) = 64

(400-64)/ (5-2) = average rate of change

Answer 9

400-64=336 and 5-2=3 so... 336/3?

Answer 10

and the average rate of change represents speed :)

Answer 11

Yes :)

Answer 12

336/3=112

Answer 13

Correct :)

Answer 14

So since its falling down... its C?

Answer 15

Yes! :)

Answer 16

Thank You!

Answer 17

You're welcomed :)

Answer 18

lol

Answer 19

well remember that
avg of change of HEIGHT = SPEED
avg of change of SPEED = ACCELERATION
:) always true, really :)
xD