Question

Trig: http://prntscr.com/47nq1q

Answer 1

tis just a quadratic equation.... thus you can just factor it or use the quadratic formula

Answer 2

I have to go, but I'll just tell you quickly what you need to do.
Make a substitution and solve the quadratic equation. Let a = sin x.
The substitute back and solve the trig part.

Answer 3

hehe why dont u follow the hints :o

Answer 4

I was, but got a very extreme answer...

Answer 5

\(\bf \textit{quadratic formula}\\
y={\color{blue}{ 4}}sin^2(x){\color{red}{ -4}}sin(x){\color{green}{ +1}}
\qquad \qquad
x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\)

Answer 6

Thanks, j

Answer 7

answer with cool latex !

Answer 8

\(\bf \textit{quadratic formula}\\
y={\color{blue}{ 4}}sin^2(x){\color{red}{ -4}}sin(x){\color{green}{ +1}}
\qquad \qquad
sin(x)= \cfrac{ - {\color{red}{ -4}} \pm \sqrt { {\color{red}{ (-4)}}^2 -4{\color{blue}{ (4)}}{\color{green}{ (1)}}}}{2{\color{blue}{ (4)}}}
\\ \quad \\
sin(x)=\cfrac{4\pm\sqrt{16-16}}{8}\)

Answer 9

and then you simply take the \(\bf sin^{-1}\) to both sides to get the angles