Question

Seriously need quick help!!! I only have 20mins!!! Getting confused on some of this algebra... http://prntscr.com/47o33k

Answer 1

plug it into your algebraic calculator.

Answer 2

I don't have one

Answer 3

Can you link an inline one?

Answer 4

online*

Answer 5

@dumbcow

Answer 6

wolframalpha.com

Answer 7

Thanks, but can you explain how to do the algebra? THat's where I'm lost. Wolfram Doesn't explain how to get to x.

Answer 8

Then one more question: http://prntscr.com/47o9m5

Answer 9

sure do you want to input g(x) into f(x)
\[\frac{g(x) - 7}{g(x)+3}\]
if that equals "x" then its an inverse
the algebra really has to do with combining fractions and simplifying
\[g(x) - 7 = \frac{-3x-7}{x-1} - 7 = \frac{(-3x-7)-7(x-1)}{x-1} = \frac{-10x}{x-1}\]

Answer 10

How would I divide a fraction by a fraction?

Answer 11

multiply by reciprocal

\[\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b}*\frac{d}{c}\]

Answer 12

Can you do this one, now? http://prntscr.com/47o9m5

Answer 13

use trig identity for double angle for cos
\[\cos 2 \theta = 1-2 \sin^2 \theta\]
Note 4x = 2(2x)

Answer 14

So how would I make 2sin^2x be equal to cos 4x?

Answer 15

Wait. Using that Identity, you can only use it twice. There is an extra Cos2x on the left side, so is this no solution?

Answer 16

i dont follow , what extra cos2x ? j

Answer 17

leave the right side alone

make the substitutions on left side

add 1+1 = 2 and you are done .... left side = right side