A train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train's acceleration be described?
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We can find the acceleration of the train by using the equation \(\sf V=U+at\), here, v and u are the final and initial speeds of the train. 10=25+a\(\times\)240 -->a=-0.0625 m/s\(^2\) The negative sign means that the acceleration is basically acting against the motion i.e it's retardation.
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